Last Updated on September 8, 2024 by XAM CONTENT
Hello students, we are providing case study questions for class 8 maths. Case study questions are the new question format that is introduced in CBSE board. The resources for case study questions are very less. So, to help students we have created chapterwise case study questions for class 8 maths. In this article, you will find case study questions for CBSE Class 8 Maths Chapter 9 Mensuration. It is a part of Case Study Questions for CBSE Class 8 Maths Series.
| Chapter | Mensuration |
| Type of Questions | Case Study Questions |
| Nature of Questions | Competency Based Questions |
| Board | CBSE |
| Class | 8 |
| Subject | Maths |
| Useful for | Class 8 Studying Students |
| Answers provided | Yes |
| Difficulty level | Mentioned |
| Important Link | Class 8 Maths Chapterwise Case Study |
Case Study Questions on Mensuration
Questions
Passage 1:
Rahul went to the market and purchased a beautiful box for jewellery. The external dimensions of a closed box are 80 cm by 56 cm by
40 cm. The wood is 2.5 cm thick all around.
On basis of this information given in passage answer following questions.
Q. 1. Find the capacity of the box.
(a) 123875 cm3
(b) 194865 cm3
(c) 133875 cm3
(d) 133975 cm3
Difficulty Level: Easy
Ans. Option (c) is correct.
Explanation: L = 80 – 2(2.5) = 75cm
H = 40 – 2(2.5) = 35cm
Capacity of box = Volume = l × b × h = 75 × 51 × 35 = 133875 cm3.
Hence capacity of box = 133875 cm3
Q. 2. Find the external volume of box.
(a) 179200 cm3
(b) 197200 cm3
(c) 169700 cm3
(d) 198200 cm3
Difficulty Level: Easy
Ans. Option (a) is correct.
Explanation: L= 80cm
B = 56cm
H = 40cm
External volume = 80 × 56 × 40 = 179200 cm3
Q. 3. The volume of the wood used in making the box.
(a) 45325 cm3
(b) 32543 cm3
(c) 23465 cm3
(d) 34285 cm3
Difficulty Level: Easy
Ans. Option (a) is correct.
Explanation: Volume of wood used
= External volume – Internal volume
= 179200 – 133875 = 45325 cm3
Q. 4. Find the length of ribbon required to cover all its edges.
Difficulty Level: Easy
Sol. There are 4l, 4b, 4h as edges
Therefore, length of ribbon required to cover all its edges
= 4l + 4b + 4h = 4(l + b + h)
=4(80 + 56 + 40) = 4 × 176 = 704 cm
Q. 5. How much sheet of paper he needs to cover the box completely?
Difficulty Level: Easy
Sol. To cover the box completely paper needed
= Total surface area of cuboid
Total surface area of cuboid = 2(lb + bh + hl)
= 2(80 × 56 + 56 × 40 + 40 × 80)
= 2(4480 + 2240 + 3200)
= 2 × 9920 = 19840 cm2
Also check
- Direct and Inverse Proportions Class 8 Case Study Questions Maths Chapter 11
- Exponents and Powers Class 8 Case Study Questions Maths Chapter 10
- Mensuration Class 8 Case Study Questions Maths Chapter 9
- Algebraic Expressions and Identities Class 8 Case Study Questions Maths Chapter 8
- Comparing Quantities Class 8 Case Study Questions Maths Chapter 7
- Cube and Cube Roots Class 8 Case Study Questions Maths Chapter 6
- Square and Square Roots Class 8 Case Study Questions Maths Chapter 5
- Data Handling Class 8 Case Study Questions Maths Chapter 4
- Understanding Quadrilaterals Class 8 Case Study Questions Maths Chapter 3
- Linear Equations in One Variable Class 8 Case Study Questions Maths Chapter 2
- Rational Numbers Class 8 Case Study Questions Maths Chapter 1
Download eBooks for CBSE Class 8 Maths
- Rational Numbers Topicwise Worksheet for CBSE Class 8 Maths
- Linear Equations in One Variable Worksheet for CBSE Class 8 Maths
- Understanding Quadrilaterals Worksheet for CBSE Class 8 Maths
- Data Handling Worksheet for CBSE Class 8 Maths
- Squares and Square Roots Worksheet for CBSE Class 8 Maths
- Cube and Cube Roots Worksheet for CBSE Class 8 Maths
- Comparing Quantities Worksheet for CBSE Class 8 Maths
- Algebraic Expressions and Identities Worksheet for CBSE Class 8 Maths
Topics from which case study questions may be asked
- Area of a Polygon
- Solid Shapes
- Surface Area of Cube, Cuboid and Cylinder
- Volume of Cube, Cuboid and Cylinder
- Volume and Capacity
Polygon is a closed shaped made up of line segments with no end point.
To find area of a polygon divide it into triangles and quadrilaterals then find the area of triangles and quadrilaterals then add them.
Polygon can be Regular and irregular
Polygons having all its sides and angles equal are Regular Polygon.
Case study questions from the above given topic may be asked.
Important Keywords
Right Circular Cylinder: When cylinder two circular faces are congruent and are parallel to each other and a line segment joining the center of circular faces is perpendicular to base it is called Right Circular Cylinder.
Lateral Surface Area: It is an area of curved surface of a shape therefore it is also called curved surface area
Frequently Asked Questions (FAQs) on Mensuration Case Study
Q1: What is Mensuration in Class 8 Maths?
A1: Mensuration refers to the branch of mathematics that deals with the measurement of various geometric figures such as area, perimeter, surface area, and volume of 2D and 3D shapes. In Class 8, students learn to calculate these parameters for figures like rectangles, triangles, cubes, cuboids, and cylinders.
Q2: What are the important topics covered in Chapter 9 Mensuration?
A2: The key topics include:
Area of polygons
Surface area and volume of cubes, cuboids, and cylinders
Volume and capacity of 3D shapes
Q3: How do you calculate the surface area of a cuboid?
A3: The surface area of a cuboid is calculated using the formula:
Surface Area = 2 (lb + bh + hl)
Surface Area=2(lb+bh+hl)
where l is the length, b is the breadth, and h is the height of the cuboid.
Q4: What is the difference between volume and capacity?
A4: Volume refers to the amount of space an object occupies.
Capacity is the quantity of substance a container can hold, generally used for liquids.
Q5: What are some common errors students make in Mensuration?
A5: Common errors include confusing units of measurement (e.g., using square units for area and cubic units for volume), misapplying formulas, and not paying attention to the dimensions of figures while calculating areas and volumes.
Q6: What is the formula for finding the volume of a cylinder?
A6: The volume of a cylinder is calculated using the formula:
V = πr2h
where 𝑟 is the radius of the base, and ℎ is the height.
Q7: How do students prepare effectively for the Mensuration chapter?
A7: Students should focus on practicing a variety of problems from each section, understanding the formulas, and revising regularly using NCERT solutions and reference materials that provide step-by-step explanations.
Q8: Are there any online resources or tools available for practicing Mensuration case study questions?
A8: We provide case study questions for CBSE Class 8 Maths on our website. Students can visit the website and practice sufficient case study questions and prepare for their exams. If you need more case study questions, then you can visit Physics Gurukul website. they are having a large collection of case study questions for all classes.
