Motion Class 9 Case Study Questions Science Chapter 7

A1: Case study questions in CBSE examinations typically involve scenarios or real-life examples, requiring students to apply their understanding of concepts to solve problems or analyze situations.

A2: Case study questions provide a practical context for students to apply theoretical knowledge to real-world situations, fostering deeper understanding and critical thinking skills.

A3: Students should carefully read the case study, identify the key issues or problems presented, analyze the information provided, apply relevant concepts and principles of chemical reactions and equations, and formulate well-supported solutions or responses.

A4: Yes, several educational websites offer case study questions for CBSE students preparing for science examinations. We also offer a collection of case study questions for all classes and subject on our website. Visit our website to access these questions and enhance your learning experience. If you need more case study questions for your preparation, then you visit Physics Gurukul website.

A5: Effective preparation strategies include regular revision of concepts, solving practice questions, analyzing case studies from previous exams, seeking clarification on doubts, and consulting with teachers or peers for guidance and support.

A6: Teachers can integrate case studies into lesson plans, group discussions, or interactive activities to engage students in active learning, promote problem-solving skills, and facilitate a deeper understanding of “Motion”.

A7: Distance is the actual path length travelled by an object, irrespective of direction.
Displacement is the shortest straight-line distance between initial and final positions, along with direction.
Distance is scalar; displacement is vector.

A8: No.
Distance can be zero only if the object doesn’t move.
But if it moves, displacement becomes zero only when the object returns to its starting point.
So distance = 0 and displacement ≠ 0 is not possible.

A9: After one full revolution the final position = initial position.
Hence displacement = 0, but distance = circumference of the circle.

A10: Average speed = total distance / total time
Average velocity = total displacement / total time
If displacement = 0 (e.g., round trip), average velocity becomes 0 but average speed is non-zero.

A11: When total displacement is zero.
Example: A person goes from home to school (1 km) and returns home.
Total distance = 2 km, but displacement = 0 → average velocity = 0.

A12: Speed of the object.
Higher slope = higher speed.
A straight line shows uniform speed; a curved line shows non-uniform speed.

A13: Acceleration.
Positive slope → acceleration
Negative slope → retardation
Zero slope → uniform velocity

A14: If a body covers equal distances in equal intervals of time, it is in uniform motion.
Example: A car moving at a steady speed of 60 km/h.

A15: It shows constant (uniform) velocity and zero acceleration.

A16: Because the motion is one-dimensional. The object moves only in one direction, so a single coordinate (x) fully describes its position.

A17: Negative acceleration (retardation) occurs when velocity decreases with time.
Example: A car applying brakes and slowing down from 50 km/h to 20 km/h.

A18: If a body starts from rest, its initial velocity u = 0.

A19: Displacement of the object.
Area = velocity × time = displacement (for uniform velocity).

A20: Because it has both magnitude and direction.
Example: 5 m east.

A21: No. Speed is scalar and cannot be negative.
Velocity can be negative because it has direction, but speed is always positive or zero.