Last Updated on April 21, 2025 by XAM CONTENT
Hello students, we are providing case study questions for class 11 Physics. Case study questions are the new question format that is introduced in CBSE board. The resources for case study questions are very less. So, to help students we have created chapterwise case study questions for class 11 Physics. In this article, you will find case study questions for cbse class 11 Physics chapter 8 Mechanical Properties of Solids.
Chapter | Mechanical Properties of Solids |
Type of Questions | Case Study Questions |
Nature of Questions | Competency Based Questions |
Board | CBSE |
Class | 11 |
Subject | Physics |
Useful for | Class 11 Studying Students |
Answers provided | Yes |
Difficulty level | Mentioned |
Important Link | Class 11 Physics Chapterwise Case Study |
Case Study Questions on Mechanical Properties of Solids
Case Study Question 1
Stress and Strain in a Wire
Passage:
A metal wire of original length L = 2 m and cross-sectional area A = 1 mm² is stretched by applying a force of 100 N. The student observes that the extension in length is ΔL = 1 mm. She is asked to calculate stress, strain, and Young’s modulus using standard formulas.
Q1. What is the stress in the wire?
(a) $10^6 \mathrm{~Pa}$
(b) $10^7 \mathrm{~Pa}$
(c) $10^8 \mathrm{~Pa}$
(d) $10^5 \mathrm{~Pa}$
Answer: (c)
Explanation:
$$
\text { Stress }=\frac{F}{A}=\frac{100}{1 \times 10^{-6}}=10^8 \mathrm{~Pa}
$$
Q2. What is the strain produced in the wire?
(a) 0.0005
(b) 0.001
(c) 0.01
(d) 0.1
Answer: (b)
Explanation:
$$
\text { Strain }=\frac{\Delta L}{L}=\frac{1 \times 10^{-3}}{2}=0.0005
$$
Q3. What is the Young’s modulus of the material?
(a) $2 \times 10^{11} \mathrm{~Pa}$
(b) $1 \times 10^{11} \mathrm{~Pa}$
(c) $5 \times 10^{10} \mathrm{~Pa}$
(d) $1 \times 10^{10} \mathrm{~Pa}$
Answer: (a)
Explanation:
$$
Y=\frac{\text { Stress }}{\text { Strain }}=\frac{10^8}{0.0005}=2 \times 10^{11} \mathrm{~Pa}
$$
Q4. What type of deformation is shown in this case?
(a) Plastic deformation
(b) Temporary strain
(c) Elastic deformation
(d) Shearing
Answer: (c)
Explanation:
Since the wire returns to its original length when force is removed, it is elastic deformation.
Case Study Question 2
Spring Constant and Elastic Potential Energy
Passage:
A student stretches a spring by 5 cm using a force of 10 N . She is asked to calculate the spring constant (k) and the potential energy stored in the stretched spring using:
– Hooke’s law: $F=k x$
– Elastic potential energy: $U=\frac{1}{2} k x^2$
Q1. What is the spring constant of the spring?
(a) $100 \mathrm{~N} / \mathrm{m}$
(b) $200 \mathrm{~N} / \mathrm{m}$
(c) $300 \mathrm{~N} / \mathrm{m}$
(d) $400 \mathrm{~N} / \mathrm{m}$
Answer: (b)
Explanation:
$$
k=\frac{F}{x}=\frac{10}{0.05}=200 \mathrm{~N} / \mathrm{m}
$$
Q2. What is the potential energy stored in the spring?
(a) 0.25 J
(b) 0.5 J
(c) 1.25 J
(d) 2 J
Answer: (a)
Explanation:
$$
U=\frac{1}{2} \times 200 \times(0.05)^2=0.25 \mathrm{~J}
$$
Q3. If the spring is stretched twice as much, how does the potential energy change?
(a) Remains same
(b) Doubles
(c) Quadruples
(d) Triples
Answer: (c)
Explanation:
Elastic potential energy $\propto x^2$. If $x$ is doubled, energy becomes $4 U$.
Q4. What type of stress is acting in the spring during stretching?
(a) Bulk stress
(b) Shear stress
(c) Tensile stress
(d) Compressive stress
Answer: (c)
Explanation:
A spring being stretched experiences tensile stress (pulling force along its length).
Case Study Question 3
Elastic Limit and Plastic Deformation
Passage:
A wire is subjected to increasing load in a lab. Initially, the extension is proportional to the load (obeying Hooke’s Law). Beyond a certain point (called elastic limit), the wire doesn’t return to its original length. Further loading leads to plastic deformation and finally breaking of the wire.
Q1. What is the region where Hooke’s law is valid?
(a) Yield point
(b) Plastic region
(c) Beyond elastic limit
(d) Proportional limit
Answer: (d)
Explanation:
Hooke’s Law is valid only in the proportional limit, where stress ∝ strain.
Q2. What is the behavior of the wire beyond the elastic limit?
(a) It regains original shape
(b) It shows perfect elasticity
(c) It undergoes permanent deformation
(d) It becomes a superconductor
Answer: (c)
Explanation:
Beyond elastic limit, material shows plastic deformation — permanent change in shape.
Q3. What is the point just before the wire breaks called?
(a) Elastic limit
(b) Breaking point
(c) Yield point
(d) Ultimate tensile strength
Answer: (d)
Explanation:
Ultimate tensile strength (UTS) is the maximum stress the material can bear before breaking.
Q4. Which of the following materials is most elastic?
(a) Rubber
(b) Copper
(c) Steel
(d) Plastic
Answer: (c)
Explanation:
Steel is most elastic because it returns to its original shape better than others (elastic modulus is high).
We hope the given case study questions for Mechanical Properties of Solids Class 11 helps you in your learning.
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Topics from which case study questions may be asked
- Stress-strain relationship
- Hooke’s law
- Elastic modulus
- Applications of elasticity
Hooke’s Law states that the stress is proportional to strain within the elastic limit — foundational in elasticity.
For further practice on case study questions related to Mechanical Properties of Solids Class 11 Physics, we recommend exploring the link given below.
Frequently Asked Questions (FAQs) on Mechanical Properties of Solids Case Study Questions
Q1: What are case study questions in Mechanical Properties of Solids?
A1: Case study questions in Mechanical Properties of Solids test your ability to apply concepts in real-life scenarios.
Q2: Are these questions asked in board exams?
A2: Yes, CBSE has started including case study/competency-based questions in final exams.
Q3: How should I prepare for case study questions?
A3: Focus on understanding concepts and practicing application-based problems.
Q4: Are answers provided for Class 11 Physics Mechanical Properties of Solids case study questions?
A4: Yes, detailed answers are provided for all questions.
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