{"id":2459,"date":"2026-11-13T18:58:27","date_gmt":"2026-11-13T13:28:27","guid":{"rendered":"https:\/\/xamcontent.com\/cisce\/?p=2459"},"modified":"2026-11-13T18:58:28","modified_gmt":"2026-11-13T13:28:28","slug":"icse-class-10-chemistry-2023-question-paper-with-solutions","status":"publish","type":"post","link":"https:\/\/xamcontent.com\/cisce\/icse-class-10-chemistry-2023-question-paper-with-solutions\/","title":{"rendered":"ICSE Class 10 Chemistry 2023 Question Paper with Solutions"},"content":{"rendered":"<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_68_1 counter-hierarchy ez-toc-counter ez-toc-grey ez-toc-container-direction\">\n<div class=\"ez-toc-title-container\">\n<p class=\"ez-toc-title \" >Table of Contents<\/p>\n<span class=\"ez-toc-title-toggle\"><a href=\"#\" class=\"ez-toc-pull-right ez-toc-btn ez-toc-btn-xs ez-toc-btn-default ez-toc-toggle\" aria-label=\"Toggle Table of Content\"><span class=\"ez-toc-js-icon-con\"><span class=\"\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #999;color:#999\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #999;color:#999\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/span><\/a><\/span><\/div>\n<nav><ul class='ez-toc-list ez-toc-list-level-1 eztoc-toggle-hide-by-default' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/xamcontent.com\/cisce\/icse-class-10-chemistry-2023-question-paper-with-solutions\/#ICSE_Chemistry_2023_%E2%80%94_Section_A\" title=\"ICSE Chemistry 2023 \u2014 Section A\">ICSE Chemistry 2023 \u2014 Section A<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/xamcontent.com\/cisce\/icse-class-10-chemistry-2023-question-paper-with-solutions\/#ICSE_Chemistry_2023_%E2%80%94_Section_B\" title=\"ICSE Chemistry 2023 \u2014 Section B\">ICSE Chemistry 2023 \u2014 Section B<\/a><\/li><\/ul><\/nav><\/div>\n<span class=\"rt-reading-time\" style=\"display: block;\"><span class=\"rt-label rt-prefix\">Reading Time: <\/span> <span class=\"rt-time\">24<\/span> <span class=\"rt-label rt-postfix\">minutes<\/span><\/span>\n<div class=\"xc-nd xc-icse-physics-pyq xc-icse-chemistry-pyq\">\n<div class=\"xc-intro-box\"><div class=\"xc-intro-label\">ICSE Class 10 Chemistry PYQ<\/div><p class=\"xc-intro-text\">Practice the complete <strong>ICSE Class 10 Chemistry 2023 Question Paper with Solutions<\/strong>, including MCQs, chemical equations, electrolysis, analytical chemistry, organic chemistry, metallurgy and numericals. Use this solved paper to revise important concepts, practise board-style questions and strengthen your exam preparation.<\/p><\/div>\n<div class=\"xc-info-grid\"><div class=\"xc-info-card\"><div class=\"xc-info-card-label\">Year<\/div><div class=\"xc-info-card-value\">2023<\/div><\/div><div class=\"xc-info-card\"><div class=\"xc-info-card-label\">Maximum Marks<\/div><div class=\"xc-info-card-value\">80<\/div><\/div><div class=\"xc-info-card\"><div class=\"xc-info-card-label\">Time Allowed<\/div><div class=\"xc-info-card-value\">Two hours<\/div><\/div><\/div>\n<div class=\"xc-set\"><div class=\"xc-set-header\"><div class=\"xc-set-icon\">\ud83d\udcc4<\/div><div><div class=\"xc-set-title\">Paper Instructions<\/div><div class=\"xc-set-sub\">ICSE Class 10 Chemistry 2023<\/div><\/div><\/div><div class=\"xc-qtext\"><p>Answer to this paper must be written on the paper provided separately.<\/p><p>You will not be allowed to write during the first 15 minutes. This time is to be spent in reading the question paper.<\/p><p>The time given at the head of this Paper is the time allowed for writing the answers.<\/p><p>Section A is compulsory. Attempt any four questions from Section B.<\/p><p>The intended marks for questions or parts of questions are given in brackets [ ].<\/p><\/div><\/div>\n<div class=\"xc-section-heading\"><div class=\"xc-section-heading-icon\">\u2713<\/div><div class=\"xc-section-heading-body\"><div class=\"xc-section-heading-label\">Section A<\/div><h2 class=\"xc-section-heading-title\"><span class=\"ez-toc-section\" id=\"ICSE_Chemistry_2023_%E2%80%94_Section_A\"><\/span>ICSE Chemistry 2023 \u2014 Section A<span class=\"ez-toc-section-end\"><\/span><\/h2><div class=\"xc-section-heading-sub\">40 marks \u2022 Section A is compulsory.<\/div><\/div><div class=\"xc-section-heading-stat\"><div class=\"xc-section-heading-stat-num\">40<\/div><div class=\"xc-section-heading-stat-label\">Marks<\/div><\/div><\/div>\n<div class=\"xc-set\"><div class=\"xc-set-header\"><div class=\"xc-set-icon\">1<\/div><div><div class=\"xc-set-title\">Question 1<\/div><div class=\"xc-set-sub\">Choose the correct answers from the given options.<\/div><\/div><\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q1-i\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">i<\/div><div class=\"xc-qtext\"><p>An element in period 3, whose electron affinity is zero: <strong>[1]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-options\">\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">A<\/span><span>Neon<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">B<\/span><span>Sulphur<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">C<\/span><span>Sodium<\/span><\/div>\n<div class=\"xc-opt correct\"><span class=\"xc-opt-key\">D<\/span><span>Argon<\/span><\/div>\n<\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>Option (d) is correct<\/p>\n<p><strong>Explanation:<\/strong> It is a noble gas of period 3 whose electron affinity is zero.<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q1-ii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">ii<\/div><div class=\"xc-qtext\"><p>An element with the largest atomic radius among the following is: <strong>[1]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-options\">\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">A<\/span><span>Carbon<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">B<\/span><span>Nitrogen<\/span><\/div>\n<div class=\"xc-opt correct\"><span class=\"xc-opt-key\">C<\/span><span>Lithium<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">D<\/span><span>Beryllium<\/span><\/div>\n<\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>Option (c) is correct<\/p>\n<p><strong>Explanation:<\/strong> Atomic radii decreases across the period from left to right.<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q1-iii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">iii<\/div><div class=\"xc-qtext\"><p>The compound that is not an one of aluminium: <strong>[1]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-options\">\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">A<\/span><span>Cryolite<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">B<\/span><span>Corundum<\/span><\/div>\n<div class=\"xc-opt correct\"><span class=\"xc-opt-key\">C<\/span><span>Fluorspar<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">D<\/span><span>Bauxite<\/span><\/div>\n<\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>Option (c) is correct<\/p>\n<p><strong>Explanation:<\/strong> Others are ore of aluminium. Fluorspar is \\(\\mathrm{CaF}^{+2}\\).<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q1-iv\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">iv<\/div><div class=\"xc-qtext\"><p>The vapour density of \\(\\mathbf{C H}_{\\mathbf{3}} \\mathbf{O H}\\) is ____. (At. Wt. \\(\\mathbf{C} \\boldsymbol{=} \\mathbf{1 2}, \\mathbf{H} \\boldsymbol{=} \\mathbf{1}, \\mathbf{O} \\boldsymbol{=} \\mathbf{1 6}\\) ) <strong>[1]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-options\">\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">A<\/span><span>32<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">B<\/span><span>18<\/span><\/div>\n<div class=\"xc-opt correct\"><span class=\"xc-opt-key\">C<\/span><span>16<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">D<\/span><span>34<\/span><\/div>\n<\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>Option (c) is correct<\/p>\n<p><strong>Explanation:<\/strong> Vapour density = molecular mass\/2<\/p>\n<div class=\"mathjax-overflow\">\\[\n\\begin{aligned}\n&amp; \\mathrm{CH}_{3} \\mathrm{OH}=12+3 \\times 1+16+1=32 \\\\\n&amp; \\text { V.D. }=\\frac{32}{2}=16\n\\end{aligned}\n\\]<\/div><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q1-v\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">v<\/div><div class=\"xc-qtext\"><p>Which of the following reactions takes place at the anode during the electroplating of an article with silver? <strong>[1]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-options\">\n<div class=\"xc-opt correct\"><span class=\"xc-opt-key\">A<\/span><span>\\(\\mathrm{Ag}-\\mathrm{le}^{-} \\rightarrow \\mathrm{Ag}^{1+}\\)<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">B<\/span><span>\\(\\mathrm{Ag}+\\mathrm{le}^{-} \\rightarrow \\mathrm{Ag}^{1-}\\)<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">C<\/span><span>\\(\\mathrm{Ag}-\\mathrm{le}^{-} \\rightarrow \\mathrm{Ag}\\)<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">D<\/span><span>None of the above<\/span><\/div>\n<\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>Option (a) is correct<\/p>\n<p><strong>Explanation:<\/strong> Oxidation takes place at anode<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q1-vi\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">vi<\/div><div class=\"xc-qtext\"><p>The metallic hydroxide which forms a deep inky blue solution with excess ammonium hydroxide solution is: <strong>[1]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-options\">\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">A<\/span><span>\\(\\mathrm{Fe}(\\mathrm{OH})_{2}\\)<\/span><\/div>\n<div class=\"xc-opt correct\"><span class=\"xc-opt-key\">B<\/span><span>\\(\\mathrm{Cu}(\\mathrm{OH})_{2}\\)<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">C<\/span><span>\\(\\mathrm{Ca}(\\mathrm{OH})_{2}\\)<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">D<\/span><span>\\(\\mathrm{Fe}(\\mathrm{OH})_{3}\\)<\/span><\/div>\n<\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>Option (b) is correct<\/p>\n<p><strong>Explanation:<\/strong> \\(\\mathrm{Cu}^{2+}\\) ions form deep inky blue solution.<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q1-vii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">vii<\/div><div class=\"xc-qtext\"><p>An example of a cyclic organic compound is: <strong>[1]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-options\">\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">A<\/span><span>Propene<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">B<\/span><span>Pentene<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">C<\/span><span>Butene<\/span><\/div>\n<div class=\"xc-opt correct\"><span class=\"xc-opt-key\">D<\/span><span>Benzene<\/span><\/div>\n<\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>Option (d) is correct<\/p>\n<p><strong>Explanation:<\/strong> It has all carbon atoms in a ring structure.<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q1-viii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">viii<\/div><div class=\"xc-qtext\"><p>In the laboratory preparation, HCl gas is dried by passing through: <strong>[1]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-options\">\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">A<\/span><span>dilute nitric acid<\/span><\/div>\n<div class=\"xc-opt correct\"><span class=\"xc-opt-key\">B<\/span><span>concentrated sulphuric acid<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">C<\/span><span>dilute sulphuric acid<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">D<\/span><span>acidified water<\/span><\/div>\n<\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>Option (b) is correct<\/p>\n<p><strong>Explanation:<\/strong> Other drying agents may react with HCl gas. Explanation: Other drying agents may react with HCl gas.<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q1-ix\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">ix<\/div><div class=\"xc-qtext\"><p>The nitrate which on thermal decomposition leaves behind a residue which is yellow when hot and white when cold: <strong>[1]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-options\">\n<div class=\"xc-opt correct\"><span class=\"xc-opt-key\">A<\/span><span>Lead nitrate<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">B<\/span><span>Ammonium nitrate<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">C<\/span><span>Copper nitrate<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">D<\/span><span>Zinc nitrate<\/span><\/div>\n<\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>Option (a) is correct<\/p>\n<p><strong>Explanation:<\/strong> Lead nitrate on thermal decomposition gives lead oxide which is yellow in colour.<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q1-x\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">x<\/div><div class=\"xc-qtext\"><p>The salt formed when concentrated sulphuric acid reacts with \\(\\mathbf{K N O}_{\\mathbf{3}}\\) above 200\u00b0C: <strong>[1]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-options\">\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">A<\/span><span>\\(\\mathrm{K}_{2} \\mathrm{SO}_{4}\\)<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">B<\/span><span>\\(\\mathrm{K}_{2} \\mathrm{SO}_{3}\\)<\/span><\/div>\n<div class=\"xc-opt correct\"><span class=\"xc-opt-key\">C<\/span><span>\\(\\mathrm{KHSO}_{4}\\)<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">D<\/span><span>\\(\\mathrm{KHSO}_{3}\\)<\/span><\/div>\n<\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>Option (c) is correct<\/p>\n<p><strong>Explanation:<\/strong> \\(\\mathrm{KHSO}_{4}\\), potassium bisulphate Potassium bisulphate and nitric acid is formed. The reaction takes place below 200\u00b0C because above this temperature nitric acid decomposes to nitrogen dioxide.<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q1-xi\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">xi<\/div><div class=\"xc-qtext\"><p>The property exhibited by concentrated sulphuric acid when it is used to prepare hydrogen chloride gas from potassium chloride: <strong>[1]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-options\">\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">A<\/span><span>Dehydrating property<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">B<\/span><span>Drying property<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">C<\/span><span>Oxidizing property<\/span><\/div>\n<div class=\"xc-opt correct\"><span class=\"xc-opt-key\">D<\/span><span>Non-volatile acid property<\/span><\/div>\n<\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>Option (d) is correct<\/p>\n<p><strong>Explanation:<\/strong> Due to its reducing nature it shows non-volatile acid property.<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q1-xii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">xii<\/div><div class=\"xc-qtext\"><p>The hydrocarbon formed when sodium propanoate and soda lime are heated together: <strong>[1]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-options\">\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">A<\/span><span>Methane<\/span><\/div>\n<div class=\"xc-opt correct\"><span class=\"xc-opt-key\">B<\/span><span>Ethane<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">C<\/span><span>Ethene<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">D<\/span><span>Propane<\/span><\/div>\n<\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>Option (b) is correct<\/p>\n<p><strong>Explanation:<\/strong> This is decarboxylation reaction.<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q1-xiii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">xiii<\/div><div class=\"xc-qtext\"><p>The acid which does not form acid salt by a basic radical: <strong>[1]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-options\">\n<div class=\"xc-opt correct\"><span class=\"xc-opt-key\">A<\/span><span>\\(\\mathrm{H}_{2} \\mathrm{CO}_{3}\\)<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">B<\/span><span>\\(\\mathrm{H}_{3} \\mathrm{PO}_{4}\\)<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">C<\/span><span>\\(\\mathrm{H}_{2} \\mathrm{SO}_{4}\\)<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">D<\/span><span>\\(\\mathrm{CH}_{3} \\mathrm{COOH}\\)<\/span><\/div>\n<\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>Option (a) is correct<\/p>\n<p><strong>Explanation:<\/strong> It is a weak acid so does not participate in formation of acidic salts.<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q1-xiv\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">xiv<\/div><div class=\"xc-qtext\"><p>THe general formula of hydrocarbons with single covalent bonds is: <strong>[1]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-options\">\n<div class=\"xc-opt correct\"><span class=\"xc-opt-key\">A<\/span><span>\\(\\mathrm{C}_{\\mathrm{n}} \\mathrm{H}_{2 \\mathrm{n}+2}\\)<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">B<\/span><span>\\(\\mathrm{C}_{\\mathrm{n}} \\mathrm{H}_{2 \\mathrm{n}}\\)<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">C<\/span><span>\\(\\mathrm{C}_{\\mathrm{n}} \\mathrm{H}_{2 \\mathrm{n}-2}\\)<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">D<\/span><span>\\(\\mathrm{C}_{\\mathrm{n}} \\mathrm{H}_{2 \\mathrm{n}-6}\\)<\/span><\/div>\n<\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>Option (a) is correct<\/p>\n<p><strong>Explanation:<\/strong> Alkane is hydrocarbon with single covalent bond.<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q1-xv\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">xv<\/div><div class=\"xc-qtext\"><p>The indicator which changes to pink colour in an alkaline solution is: <strong>[1]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-options\">\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">A<\/span><span>Blue Litmus<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">B<\/span><span>Methyl Orange<\/span><\/div>\n<div class=\"xc-opt\"><span class=\"xc-opt-key\">C<\/span><span>Red Litmus<\/span><\/div>\n<div class=\"xc-opt correct\"><span class=\"xc-opt-key\">D<\/span><span>Phenolphthalein<\/span><\/div>\n<\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>Option (d) is correct<\/p>\n<p><strong>Explanation:<\/strong> It is used as an indicator in acid base titrations and give pink colour in alkaline solution.<\/p><\/div>\n<\/div>\n<\/div>\n<div class=\"xc-set\"><div class=\"xc-set-header\"><div class=\"xc-set-icon\">2<\/div><div><div class=\"xc-set-title\">Question 2<\/div><div class=\"xc-set-sub\">ICSE Class 10 Chemistry 2023<\/div><\/div><\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q2-i\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">i<\/div><div class=\"xc-qtext\"><p>Match the Column A with Column B: <strong>[5]<\/strong><\/p>\n<div class=\"math-responsive\"><table><thead><tr><th><\/th><th>Column A<\/th><th><\/th><th>Column B<\/th><\/tr><\/thead><tbody><tr><td>(a)<\/td><td>Sodium Chloride<\/td><td>1.<\/td><td>has two shared pair of electrons<\/td><\/tr><tr><td>(b)<\/td><td>Methane<\/td><td>2.<\/td><td>has high melting and boiling points<\/td><\/tr><tr><td>(c)<\/td><td>Hydrogen chloride gas<\/td><td>3.<\/td><td>a greenhouse gas<\/td><\/tr><tr><td>(d)<\/td><td>Oxidation reaction<\/td><td>4.<\/td><td>has low melting and boiling points<\/td><\/tr><tr><td>(e)<\/td><td>Water<\/td><td>5.<\/td><td>\\(\\mathrm{Zn}-2 \\mathrm{e}^{-} \\rightarrow \\mathrm{Zn}^{2+}\\)<\/td><\/tr><tr><td><\/td><td><\/td><td>6.<\/td><td>\\(\\mathrm{S}+2 \\mathrm{e}^{-} \\rightarrow \\mathrm{S}^{2-}\\)<\/td><\/tr><\/tbody><\/table><\/div><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>Match the Column A with Column B: Column A<\/p>\n<p>(a) Sodium Chloride<\/p>\n<p>(b) Methane<\/p>\n<p>(c) Hydrogen chloride gas<\/p>\n<p>(d) Oxidation reaction<\/p>\n<p>(e) Water<\/p>\n<p>Column B<\/p>\n<p>2. has high melting and boiling point.<\/p>\n<p>3. a green house gas.<\/p>\n<p>1. has two shared pair of electrons<\/p>\n<p>5. \\(\\mathrm{Za}-2 \\mathrm{e}^{-} \\rightarrow \\mathrm{Zn}^{2+}\\)<\/p>\n<p>4. has low melting and boiling point.<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q2-ii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">ii<\/div><div class=\"xc-qtext\"><p>The following sketch illustrates the process of conversion of Alumina to Aluminium: Study the diagram and answer the following:<\/p>\n<div class=\"xc-post-image xc-img-very-small\"><img src=\"https:\/\/xamcontent.com\/cisce\/wp-content\/uploads\/2026\/11\/781438db-bf31-4eae-8317-a6fe0dd848c0-2_279_500_922_1166.jpg\" alt=\"ICSE Class 10 Chemistry 2023 Question 2(ii) figure\" loading=\"lazy\" decoding=\"async\"><\/div>\n<p>(a) Name the constituent of the electrolyte mixture which has a divalent metal in it.<\/p>\n<p>(b) Name the powdered substance &#8216;X&#8217; sprinkled on the surface of the electrolyte mixture.<\/p>\n<p>(c) What is the name of the process?<\/p>\n<p>(d) Write the reactions taking place at the electrodes &#8216;Y&#8217; (anode) and &#8216;Z&#8217; (cathode) respectively. <strong>[5]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) Fused alumina + cryolite + Fluorspar In \\(\\mathrm{CaF}_{2}\\) (Fluorspar) calcium is divalent metal ion.<\/p>\n<p>(b) Powdered coke is sprinkled, to reduce the heat loss by radiation.<\/p>\n<p>(c) Hall-Heroult process<\/p>\n<p>(d) At cathode (Z) : \\(2 \\mathrm{Al}^{3+}+6 \\mathrm{e}^{-} \\rightarrow 2 \\mathrm{Al}\\)<\/p>\n<p>At anode (Y) \\(6 \\mathrm{O}^{2-} \\rightarrow 3 \\mathrm{O}_{2}+12 \\mathrm{e}^{-}\\)<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q2-iii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">iii<\/div><div class=\"xc-qtext\"><p>Fill in the blanks with the choices given in the brackets:<\/p>\n<p>(a) Metals are good ____. [oxidizing agents\/reducing agents]<\/p>\n<p>(b) Non-polar covalent compounds are ____ [good\/bad] conductors of heat and electricity.<\/p>\n<p>(c) Higher the pH value of a solution, the more<\/p>\n<p>____ [acidic\/alkaline] it is.<\/p>\n<p>(d) &#8230;&#8230;&#8230;&#8230;&#8230;. [Silver chloride\/Lead chloride] is a white precipitate that is soluble in excess of Ammonium hydroxide solution.<\/p>\n<p>(e) Conversion of ethene to ethane is an example of<\/p>\n<p>____ [hydration\/hydrogenation] <strong>[5]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) Reducing agent.<\/p>\n<p>(b) Bad<\/p>\n<p>(c) Alkaline<\/p>\n<p>(d) Silver chloride<\/p>\n<p>(e) hydrogenation<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q2-iv\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">iv<\/div><div class=\"xc-qtext\"><p>State the terms\/process for the following:<\/p>\n<p>(a) The energy released when an atom in the gaseous state accepts an electron to form an anion.<\/p>\n<p>(b) Tendency of an element form chains of identical atoms.<\/p>\n<p>(c) The name of the process by which Ammonia is manufactured on a large scale.<\/p>\n<p>(d) A type of salt formed by partial replacement of hydroxyl radicals with an acid radical.<\/p>\n<p>(e) The ratio of the mass of a certain volume of gas to the same volume of hydrogen measured under the same conditions of temperature and pressure. <strong>[5]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) Electron affinity<\/p>\n<p>(b) Catenation<\/p>\n<p>(c) Haber&#8217;s process<\/p>\n<p>(d) Basic salt<\/p>\n<p>(e) Vapour density<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q2-v\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">v<\/div><div class=\"xc-qtext\"><p>(a) Given the structural formula of the following organic compounds:<\/p>\n<p>1. 2-chlorobutane<\/p>\n<p>2. Methanal<\/p>\n<p>3. But-2-yne<\/p>\n<p>(b) Given the IUPAC name of the following organic compounds:<\/p>\n\n<div class=\"xc-post-image xc-img-very-small\"><img src=\"https:\/\/xamcontent.com\/cisce\/wp-content\/uploads\/2026\/11\/image-1.png\" alt=\"ICSE Class 10 Chemistry 2023 Question 2(ii) figure\" loading=\"lazy\" decoding=\"async\"><\/div>\n\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a)<\/p>\n<div class=\"xc-post-image xc-img-very-small\"><img src=\"https:\/\/xamcontent.com\/cisce\/wp-content\/uploads\/2026\/11\/image-2.png\" alt=\"ICSE Class 10 Chemistry 2023 Question 2(ii) figure\" loading=\"lazy\" decoding=\"async\"><\/div>\n<p>(b) 1. Acetic acid<\/p>\n<p>2. Butan-2-ol<\/p><\/div>\n<\/div>\n<\/div>\n<div class=\"xc-section-heading\"><div class=\"xc-section-heading-icon\">\u270d\ufe0f<\/div><div class=\"xc-section-heading-body\"><div class=\"xc-section-heading-label\">Section B<\/div><h2 class=\"xc-section-heading-title\"><span class=\"ez-toc-section\" id=\"ICSE_Chemistry_2023_%E2%80%94_Section_B\"><\/span>ICSE Chemistry 2023 \u2014 Section B<span class=\"ez-toc-section-end\"><\/span><\/h2><div class=\"xc-section-heading-sub\">40 marks \u2022 Attempt any four questions from this Section.<\/div><\/div><div class=\"xc-section-heading-stat\"><div class=\"xc-section-heading-stat-num\">40<\/div><div class=\"xc-section-heading-stat-label\">Marks to Attempt<\/div><\/div><\/div>\n<div class=\"xc-set\"><div class=\"xc-set-header\"><div class=\"xc-set-icon\">3<\/div><div><div class=\"xc-set-title\">Question 3<\/div><div class=\"xc-set-sub\">ICSE Class 10 Chemistry 2023<\/div><\/div><\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q3-i\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">i<\/div><div class=\"xc-qtext\"><p>Identify the cation in each of the following cases:<\/p>\n<p>(a) Ammonium hydroxide solution when added to Solution B gives a white precipitate which does not dissolve in excess of ammonium hydroxide solution.<\/p>\n<p>(b) Sodium hydroxide solution when added to Solution C gives a white precipitate which is insoluble in excess of sodium hydroxide solution. <strong>[2]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) \\(\\mathrm{Pb}^{2+}\\) which gives white ppt of \\(\\mathrm{Pb}(\\mathrm{OH})_{2}\\)<\/p>\n<p>(b) \\(\\mathrm{Ca}^{2+}\\) with NaOH gives white ppt of \\(\\mathrm{Ca}(\\mathrm{OH})_{2}\\).<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q3-ii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">ii<\/div><div class=\"xc-qtext\"><p>Fill in the blanks by choosing the correct answer from the brackets:<\/p>\n<p>(a) During electrolysis, the compound ____ in its molten state liberates reddish brown fumes at the anode. \\(\\left[\\mathbf{N a C l} \/ \\mathbf{P b B r}_{\\mathbf{2}}\\right]\\)<\/p>\n<p>(b) The ion which could be discharged most readily during electrolysis is ____. \\(\\left[\\mathrm{Fe}^{2+} \/\\right.\\) \\(\\mathrm{Cu}^{2+}\\) ] <strong>[2]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) \\(\\mathrm{PbBr}_{2}\\)<\/p>\n<p>(b) \\(\\mathrm{Cu}^{2+}\\)<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q3-iii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">iii<\/div><div class=\"xc-qtext\"><p>Arrange the following as per the instruction given in the brackets:<\/p>\n<p>(a) Al, K, Mg, Ca (decreasing order of its reactivity)<\/p>\n<p>(b) N, Be, O, C (increasing order of non-metallic character)<\/p>\n<p>(c) P, Si, F, Be (decreasing order of valence electrons) <strong>[3]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) \\(\\mathrm{K}&gt;\\mathrm{Al}&gt;\\mathrm{Ca}&gt;\\mathrm{Mg}\\)<\/p>\n<p>(b) \\(\\mathrm{Be}&lt;\\mathrm{C}&lt;\\mathrm{N}&lt;\\mathrm{O}\\) (Increases across the period)<\/p>\n<p>(c) \\(\\mathrm{F}&gt;\\mathrm{P}&gt;\\mathrm{Si}&gt;\\mathrm{Be}\\) (increases across a period)<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q3-iv\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">iv<\/div><div class=\"xc-qtext\"><p>Complete and balance the following equations:<\/p>\n<p>(a) \\(\\mathrm{NH}_{4} \\mathrm{Cl}+\\mathrm{Ca}(\\mathrm{OH})_{2} \\rightarrow\\)<\/p>\n<p>(b) \\(\\mathrm{CuSO}_{4}+\\mathrm{NH}_{4} \\mathrm{OH} \\rightarrow\\)<\/p>\n<p>(c) \\(\\mathrm{Cu}+\\) Conc. \\(\\mathrm{HNO}_{3} \\rightarrow\\) <strong>[3]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) \\(2 \\mathrm{NH}_{4} \\mathrm{Cl}+\\mathrm{Ca}(\\mathrm{OH})_{2} \\rightarrow \\mathrm{CaCl}_{2}+2 \\mathrm{NH}_{3}+2 \\mathrm{H}_{2} \\mathrm{O}\\)<\/p>\n<p>(b) \\(\\mathrm{CuSO}_{4}(\\mathrm{aq})+2 \\mathrm{NH}_{4} \\mathrm{OH}(\\mathrm{aq}) \\rightarrow \\mathrm{Cu}(\\mathrm{OH})_{2}(\\mathrm{~S})+\\) \\(\\left(\\mathrm{NH}_{4}\\right)_{2} \\mathrm{SO}_{4}(\\mathrm{aq})\\)<\/p>\n<p>(c) \\(\\mathrm{Cu}+4 \\mathrm{HNO}_{3} \\rightarrow \\mathrm{Cu}\\left(\\mathrm{NO}_{3}\\right)_{2}+2 \\mathrm{NO}_{2}+2 \\mathrm{H}_{2} \\mathrm{O}\\) \\(3 \\mathrm{Cu}+8 \\mathrm{HNO}_{3} \\rightarrow 3 \\mathrm{Cu}\\left(\\mathrm{NO}_{3}\\right)_{2}+2 \\mathrm{NO}+4 \\mathrm{H}_{2} \\mathrm{O}\\) Any of the above reaction is correct.<\/p><\/div>\n<\/div>\n<\/div>\n<div class=\"xc-set\"><div class=\"xc-set-header\"><div class=\"xc-set-icon\">4<\/div><div><div class=\"xc-set-title\">Question 4<\/div><div class=\"xc-set-sub\">ICSE Class 10 Chemistry 2023<\/div><\/div><\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q4-i\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">i<\/div><div class=\"xc-qtext\"><p>State a relevant reason for the following:<\/p>\n<p>(a) Hydrogen chloride gas cannot be dried over quick lime.<\/p>\n<p>(b) Ammonia gas is not collected over water. <strong>[2]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) HCl is acidic and quicklime (CaO) is basic in nature. So they undergo chemical reaction when brought together.<\/p>\n<div class=\"mathjax-overflow\">\\[\n2 \\mathrm{HCl}+\\mathrm{CaO} \\rightarrow \\mathrm{CaCl}_{2}+\\mathrm{H}_{2} \\mathrm{O}\n\\]<\/div>\n<p>(b) Gas is highly soluble in water so cannot be collected over water.<\/p>\n<p>It is collected by downward displacement of air.<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q4-ii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">ii<\/div><div class=\"xc-qtext\"><p>Identify the alloy in each case from the given composition:<\/p>\n<p>(a) aluminium, magnesium, manganese, copper<\/p>\n<p>(b) iron, nickel, chromium, carbon <strong>[2]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) Duralumin<\/p>\n<p>(b) Stainless steel<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q4-iii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">iii<\/div><div class=\"xc-qtext\"><p>Solve the following numerical problem. Ethane burns in oxygen according to the chemical equation:<\/p>\n<div class=\"mathjax-overflow\">\\[\n2 \\mathrm{C}_{2} \\mathrm{H}_{6}+7 \\mathrm{O}_{2} \\rightarrow 4 \\mathrm{CO}_{2}+6 \\mathrm{H}_{2} \\mathrm{O}\n\\]<\/div>\n<p>If 80 ml of ethane is burnt in 300 ml of oxygen, find the composition of the resultant gaseous mixture when measured at room temperature. <strong>[3]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div>\\(2 \\mathrm{C}_{2} \\mathrm{H}_{6}+7 \\mathrm{O}_{2} \\rightarrow 4 \\mathrm{CO}_{2}+6 \\mathrm{H}_{2} \\mathrm{O}\\)\n<p>Molecular weight: 30324418 (in g\/mol)<\/p>\n<div class=\"math-responsive\"><table><thead><tr><th>\\(\\mathrm{C}_{2} \\mathrm{H}_{6}\\)<\/th><th>:<\/th><th>\\(\\mathrm{CO}_{2}\\)<\/th><\/tr><\/thead><tbody><tr><td>2<\/td><td>:<\/td><td>4<\/td><\/tr><tr><td>1<\/td><td>:<\/td><td>2<\/td><\/tr><\/tbody><\/table><\/div>\n<p>No. of moles of \\(\\mathrm{CO}_{2}\\) is twice that of \\(\\mathrm{C}_{2} \\mathrm{H}_{6}\\) So volume will also be twice. 80 ml of ethane will produce \\(2 \\times 80=160 \\mathrm{ml}\\) of \\(\\mathrm{CO}_{2}\\)<\/p>\n<div class=\"mathjax-overflow\">\\[\n\\begin{aligned}\n&amp; \\mathrm{O}_{2}: \\mathrm{C}_{2} \\mathrm{H}_{6} \\\\\n&amp; 7: 2 \\\\\n&amp; 3.5: 1\n\\end{aligned}\n\\]<\/div>\n<p>No of moles of oxygen is 3.5 times So, the volume of oxygen will also be 3.5 times. To burn 80 ml of ethane, \\(3.5 \\times 80=280.0 \\mathrm{ml}\\) of oxygen is required<\/p>\n<div class=\"mathjax-overflow\">\\[\n\\text { Remaining oxygen }=300-280=20 \\mathrm{ml}\n\\]<\/div>\n<p>The resultant gaseous mixture is 160 ml of \\(\\mathrm{CO}_{2}\\) and 20 ml of oxygen.<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q4-iv\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">iv<\/div><div class=\"xc-qtext\"><p>The following question are pertaining to the laboratory preparation of Ammonia gas from Magnesium nitride:<\/p>\n<p>(a) Write a balanced chemical equation for its preparation.<\/p>\n<p>(b) Why is this method seldom used?<\/p>\n<p>(c) How do you identify the gas formed? <strong>[3]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) \\(\\mathrm{Mg}_{3} \\mathrm{~N}_{2}+6 \\mathrm{H}_{2} \\mathrm{O} \\rightarrow 3 \\mathrm{Mg}(\\mathrm{OH})_{2}+2 \\mathrm{NH}_{3}\\)<\/p>\n<p>(b) As this is very expensive method.<\/p>\n<p>(c) Bring a rod dipped in HCl near it. Dense<\/p>\n<p>white fumes of ammonium chloride is formed.<\/p><\/div>\n<\/div>\n<\/div>\n<div class=\"xc-set\"><div class=\"xc-set-header\"><div class=\"xc-set-icon\">5<\/div><div><div class=\"xc-set-title\">Question 5<\/div><div class=\"xc-set-sub\">ICSE Class 10 Chemistry 2023<\/div><\/div><\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q5-i\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">i<\/div><div class=\"xc-qtext\"><p>Write one use of the following alloys:<\/p>\n<p>(a) Bronze<\/p>\n<p>(b) Fuse metal <strong>[2]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) Used in preparation of medals, musical instruments, as a ship propellents.<\/p>\n<p>(b) For soldering of metals.<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q5-ii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">ii<\/div><div class=\"xc-qtext\"><p>Draw the electron dot structure for the following:<\/p>\n<p>(a) Ammonium ion<\/p>\n<p>(b) A molecule of nitrogen [At. No.: \\(\\mathrm{N}=7, \\mathrm{H}=1\\) ] <strong>[2]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a)<\/p>\n<div class=\"xc-post-image xc-img-very-small\"><img src=\"https:\/\/xamcontent.com\/cisce\/wp-content\/uploads\/2026\/11\/781438db-bf31-4eae-8317-a6fe0dd848c0-4_126_174_1022_1212.jpg\" alt=\"ICSE Class 10 Chemistry 2023 Question 5(ii) solution figure\" loading=\"lazy\" decoding=\"async\"><\/div>\n<p>(b) <\/p>\n<div class=\"xc-post-image xc-img-very-small\"><img src=\"https:\/\/xamcontent.com\/cisce\/wp-content\/uploads\/2026\/11\/image-3.png\" alt=\"ICSE Class 10 Chemistry 2023 Question 5(ii) solution figure\" loading=\"lazy\" decoding=\"async\"><\/div>\n<\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q5-iii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">iii<\/div><div class=\"xc-qtext\"><p>Give a balanced chemical equation for the following conversions with conditions:<\/p>\n<p>(a) Ethene from ethanol<\/p>\n<p>(b) Ethyne from calcium carbide<\/p>\n<p>(c) Monochloromethane from methane <strong>[3]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a)<\/p>\n<div class=\"xc-post-image xc-img-very-small\"><img src=\"https:\/\/xamcontent.com\/cisce\/wp-content\/uploads\/2026\/11\/781438db-bf31-4eae-8317-a6fe0dd848c0-4_205_649_1222_1169.jpg\" alt=\"ICSE Class 10 Chemistry 2023 Question 5(iii) solution figure\" loading=\"lazy\" decoding=\"async\"><\/div>\n<p>(b) <div class=\"xc-post-image xc-img-very-small\"><img src=\"https:\/\/xamcontent.com\/cisce\/wp-content\/uploads\/2026\/11\/781438db-bf31-4eae-8317-a6fe0dd848c0-4_87_608_1435_1211.jpg\" alt=\"ICSE Class 10 Chemistry 2023 Question 5(iii) solution figure\" loading=\"lazy\" decoding=\"async\"><\/div><\/p>\n<p>(c) <div class=\"xc-post-image xc-img-very-small\"><img src=\"https:\/\/xamcontent.com\/cisce\/wp-content\/uploads\/2026\/11\/781438db-bf31-4eae-8317-a6fe0dd848c0-4_92_605_1552_1206.jpg\" alt=\"ICSE Class 10 Chemistry 2023 Question 5(iii) solution figure\" loading=\"lazy\" decoding=\"async\"><\/div><\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q5-iv\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">iv<\/div><div class=\"xc-qtext\"><p>Study the following observations and name the anions present in each of the reactions.<\/p>\n<p>(a) When a crystalline solid &#8216;P&#8217; is warmed with concentrated \\(\\mathbf{H}_{\\mathbf{2}} \\mathbf{S O}_{\\mathbf{4}}\\) and copper turnings a reddish brown gas is released.<\/p>\n<p>(b) When few drops of dilute sulphuric acid is added to Salt &#8216;R&#8217; and heated, a colourless gas is released which turns moist lead acetate paper silvery black.<\/p>\n<p>(c) When few drops of barium nitrate solution is added to the salt solution &#8216;Q&#8217;, a white precipitate is formed which is insoluble in HCl. <strong>[3]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) Copper nitrate is the compound &#8220;P&#8221;.<\/p>\n<p>\\(\\mathrm{NO}_{3}{ }^{2-}\\) (nitrate) is the anions.<\/p>\n<p>(b) \\(\\mathrm{H}_{2} \\mathrm{~S}\\) is the gas which turns moist lead acetate paper black.<\/p>\n<p>\\(\\mathrm{S}^{2-}\\) (sulphide) anions.<\/p>\n<p>(c) \\(\\mathrm{SO}_{4}{ }^{2-}\\) (sulphate) anions<\/p><\/div>\n<\/div>\n<\/div>\n<div class=\"xc-set\"><div class=\"xc-set-header\"><div class=\"xc-set-icon\">6<\/div><div><div class=\"xc-set-title\">Question 6<\/div><div class=\"xc-set-sub\">ICSE Class 10 Chemistry 2023<\/div><\/div><\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q6-i\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">i<\/div><div class=\"xc-qtext\"><p>Define\/State:<\/p>\n<p>(a) Electronegativity<\/p>\n<p>(b) Gay-Lussac&#8217;s Law of combining volumes <strong>[2]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) Electronegativity: It is the tendency of an atom in a molecule to attract the shared pair of electrons towards itself is known as electronegativity.<\/p>\n<p>(b) Gay Lussac&#8217;s Law of combining volumes: It states that, whenever the gases react, they always do so in volumes , which bear a simple whole number ratio to one another as well as to the gaseous products, if gaseous, all volumes being measured under similar condition of temperature and pressure.<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q6-ii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">ii<\/div><div class=\"xc-qtext\"><p>The Empirical formula of an organic compound is \\(\\mathbf{C H C l}_{\\mathbf{2}}\\). If its relative molecular mass is 168, what is its molecular formula? [At. Wt. \\(\\mathbf{C}=\\mathbf{1 2}, \\mathbf{H}=\\mathbf{1}, \\mathbf{C l}=\\mathbf{3 5 . 5}\\) ] <strong>[2]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div>\\(\\mathrm{CHCl}_{2}\\)\n<div class=\"mathjax-overflow\">\\[\n\\begin{aligned}\n\\text { Molecular mass } &amp; =12+1+2 \\times 35.5 \\\\\n&amp; =13+71.0 \\\\\n&amp; =84.0\n\\end{aligned}\n\\]<\/div>\n<div class=\"mathjax-overflow\">\\[\nn=\\text { relative molecular mass\/ }\n\\]<\/div>\n<p>empirical formula mass<\/p>\n<div class=\"mathjax-overflow\">\\[\nn=\\frac{168}{84}=2\n\\]<\/div>\n<p>molecular formula = (empirical formula)n<\/p>\n<div class=\"mathjax-overflow\">\\[\n\\left(\\mathrm{CHCl}_{2}\\right)_{2}=\\mathrm{C}_{2} \\mathrm{H}_{2} \\mathrm{Cl}_{4}\n\\]<\/div><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q6-iii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">iii<\/div><div class=\"xc-qtext\"><p>Choose the substances given in the box below to answer the following questions:<\/p>\n<div class=\"math-responsive\"><table><thead><tr><th>Iron<\/th><th>Magnesium sulphite<\/th><th>Zinc<\/th><th>Sodium sulphide<\/th><\/tr><\/thead><tbody><tr><td>Lead<\/td><td>Ferric chloride<\/td><td>Copper<\/td><td>Ferrous sulphate<\/td><\/tr><\/tbody><\/table><\/div>\n<p>(a) The metal that will not produce hydrogen gas when reacted with dilute acids.<\/p>\n<p>(b) The compound that will produce sulphur dioxide gas when reacted with dilute HCl.<\/p>\n<p>(c) The solution of this compound produces dirty green precipitate with NaOH. <strong>[3]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) Copper: It does not show reaction with acids.<\/p>\n<p>(b) Magnesium Sulphite: \\(\\mathrm{MgSO}_{3}+\\) dil. HCl \u2192 \\(\\mathrm{MgCl}_{2}+\\mathrm{H}_{2} \\mathrm{O}+\\mathrm{SO}_{2}\\)<\/p>\n<p>(c) Ferrous Sulphite: It gives dirty green ppt with NaOH<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q6-iv\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">iv<\/div><div class=\"xc-qtext\"><p>State one relevant observation for each of the following:<\/p>\n<p>(a) To the copper nitrate solution, initially few drops of sodium hydroxide solution is added and then added in excess.<\/p>\n<p>(b) Burning of ammonia in excess of oxygen.<\/p>\n<p>(c) Dry ammonia gas is passed over heated PbO. <strong>[3]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) Initially light blue ppt of \\(\\mathrm{Cu}(\\mathrm{OH})_{2}\\) is formed along with sodium nitrate.<\/p>\n<div class=\"mathjax-overflow\">\\[\n\\mathrm{Cu}\\left(\\mathrm{NO}_{3}\\right)_{2}+2 \\mathrm{NaOH} \\rightarrow \\mathrm{Cu}(\\mathrm{OH})_{2}+2 \\mathrm{NaNO}_{3}\n\\]<\/div>\n<p>The ppt is soluble in excess NaOH solution giving a deep blue coloured solution.<\/p>\n<p>(b) It burns with yellowish green flame due to the formation of \\(\\mathrm{NO}_{2}\\).<\/p>\n<p>(c) Lead monoxide is reduced to grey coloured lead.<\/p><\/div>\n<\/div>\n<\/div>\n<div class=\"xc-set\"><div class=\"xc-set-header\"><div class=\"xc-set-icon\">7<\/div><div><div class=\"xc-set-title\">Question 7<\/div><div class=\"xc-set-sub\">ICSE Class 10 Chemistry 2023<\/div><\/div><\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q7-i\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">i<\/div><div class=\"xc-qtext\"><p>Name the following:<\/p>\n<p>(a) Organic compounds with same molecular formula but different structural formula.<\/p>\n<p>(b) Group of organic compounds where the successive members follow a regular structural pattern, successive compounds differ by a &#8216; \\(\\mathrm{CH}_{2}\\) &#8216; group <strong>[2]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) Isomers: The compounds with same molecular formula and different structural formulae<\/p>\n<p>(b) Homologous series<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q7-ii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">ii<\/div><div class=\"xc-qtext\"><p>Give reason for the following:<\/p>\n<p>(a) lonisation potential decreases down a group.<\/p>\n<p>(b) lonic compounds do not conduct electricity in solid state. <strong>[2]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) Ionization potential decreases as we go down the group because as we go down:<\/p>\n<p>Atomic size increases, so the force of attraction between nucleus and valence electron reduces. It becomes easy to remove the electron.<\/p>\n<p>(b) In solid state the ions are not free to move While in molten state they can easy travel in solution thus allowing electricity to flow.<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q7-iii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">iii<\/div><div class=\"xc-qtext\"><p>Calculate:<\/p>\n<p>(a) The percentage of phosphate in the fertilizer super phosphate \\(\\mathrm{Ca}\\left(\\mathrm{H}_{2} \\mathrm{PO}_{4}\\right)_{2}\\) correct to 1 decimal point.<\/p>\n<div class=\"mathjax-overflow\">\\[\n[\\text { At. Wt. } \\mathrm{H}=1, \\mathrm{P}=31, \\mathrm{O}=16, \\mathrm{Ca}=40]\n\\]<\/div>\n<p>(b) Write the empirical formula of \\(\\mathbf{C}_{\\mathbf{8}} \\mathbf{H}_{\\mathbf{1 8}}\\). <strong>[3]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) Molecular weight \\(=\\mathrm{Ca}\\left(\\mathrm{H}_{2} \\mathrm{PO}_{4}\\right)_{2}\\)<\/p>\n<div class=\"mathjax-overflow\">\\[\n\\begin{aligned}\n&amp; 40+(2 \\times(2 \\times 1+31+4 \\times 16) \\\\\n&amp; 40+(2(2+31+64) \\\\\n&amp; 40+2(97) \\\\\n&amp; 40+194 \\\\\n&amp; =234\n\\end{aligned}\n\\]<\/div>\n<p>Amount of \\(\\mathrm{P}=2 \\times 31=62 \\mathrm{~g}\\)<\/p>\n<div class=\"mathjax-overflow\">\\[\n\\begin{aligned}\n&amp; \\text { Percentage of phosphorus }=\\frac{62 \\times 100}{234} \\\\\n&amp; =26.5 \\%\n\\end{aligned}\n\\]<\/div>\n<p>(b) Empirical formula for \\(\\mathrm{C}_{8} \\mathrm{H}_{18}\\)<\/p>\n<p>C : H 8 : 18 4 : 9 Thus empirical formula is \\(\\mathrm{C}_{4} \\mathrm{H}_{9}\\).<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q7-iv\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">iv<\/div><div class=\"xc-qtext\"><p>Answer the following questions with reference to electrorefining of copper:<\/p>\n<p>(a) What is the anode made of?<\/p>\n<p>(b) What do you observe at the cathode?<\/p>\n<p>(c) Write the reaction taking place at the cathode. <strong>[3]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) A block of impure copper metal<\/p>\n<p>(b) At cathode, cupric ions get discharged by gaining electrons from the cathode.<\/p>\n<p>Reddish brown copper is deposited at cathode.<\/p>\n<p>(c) \\(\\mathrm{Cu}^{2+}+2 \\mathrm{e}^{-} \\rightarrow \\mathrm{Cu}\\)<\/p><\/div>\n<\/div>\n<\/div>\n<div class=\"xc-set\"><div class=\"xc-set-header\"><div class=\"xc-set-icon\">8<\/div><div><div class=\"xc-set-title\">Question 8<\/div><div class=\"xc-set-sub\">ICSE Class 10 Chemistry 2023<\/div><\/div><\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q8-i\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">i<\/div><div class=\"xc-qtext\"><p>Arrange the following according to the instructions given in brackets:<\/p>\n<p>(a) \\(\\mathrm{C}_{2} \\mathrm{H}_{2}, \\mathrm{C}_{3} \\mathrm{H}_{6}, \\mathrm{CH}_{4}, \\mathrm{C}_{2} \\mathrm{H}_{4}\\) (In the increasing order of the molecular weight)<\/p>\n<p>(b) \\(\\mathrm{Cu}^{2+}, \\mathrm{Na}^{+}, \\mathrm{Zn}^{2+}, \\mathrm{Ag}^{+}\\)(The order of Preferential discharge at the cathode) <strong>[2]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a)<\/p>\n<div class=\"mathjax-overflow\">\\[\n\\begin{aligned}\n\\mathrm{C}_{2} \\mathrm{H}_{2} &amp; =2 \\times 12+2 \\times 1 \\\\\n&amp; =24+2=26 \\mathrm{~g} \\\\\n\\mathrm{C}_{3} \\mathrm{H}_{4} &amp; =36+4=40 \\mathrm{~g} \\\\\n\\mathrm{CH}_{4} &amp; =16 \\mathrm{~g} \\\\\n\\mathrm{C}_{2} \\mathrm{H}_{4} &amp; =28 \\mathrm{~g} \\\\\n\\mathrm{CH}_{4}&lt;\\mathrm{C}_{2} \\mathrm{H}_{2}&lt; &amp; \\mathrm{C}_{2} \\mathrm{H}_{4}&lt;\\mathrm{C}_{3} \\mathrm{H}_{4}\n\\end{aligned}\n\\]<\/div>\n<p>(b) \\(\\mathrm{Ag}^{+}&gt;\\mathrm{Cu}^{2+}&gt;\\mathrm{Zn}^{2+}&gt;\\mathrm{Na}^{+}\\)<\/p>\n<p>Elements at lower position get discharged easily.<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q8-ii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">ii<\/div><div class=\"xc-qtext\"><p>Differentiate between the following pairs based on the criteria given in the brackets:<\/p>\n<p>(a) Cane sugar and hydrated copper sulphate [using concentrated \\(\\mathrm{H}_{2} \\mathrm{SO}_{4}\\) ]<\/p>\n<p>(b) Sulphuric acid and hydrochloric acid [type of salts formed] <strong>[2]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) Cane sugar: Results in the formation of black spongy mass of carbon known as sugar charcoal.<\/p>\n<p>Copper sulphate: The blue crystal changes to white powder due to dehydration.<\/p>\n<p>(b) The salts of sulphuric acid are sulphates and bisulphates.<\/p>\n<p>e.g., \\(\\mathrm{NaHSO}_{4}\\) while the salts of hydrochloric acid contains \\(\\mathrm{Cl}^{-}\\)ions.<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q8-iii\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">iii<\/div><div class=\"xc-qtext\"><p>Convert the following reactions into a balanced chemical equation:<\/p>\n<p>(a) Ammonia to nitric oxide using oxygen and platinum catalyst.<\/p>\n<p>(b) Sodium hydroxide to sodium sulphate using sulphuric acid.<\/p>\n<p>(c) Ferrous sulphide to hydrogen sulphide using hydrochloric acid. <strong>[3]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) \\(4 \\mathrm{NH}_{3}+5 \\mathrm{O}_{2} \\rightarrow 4 \\mathrm{NO}+6 \\mathrm{H}_{2} \\mathrm{O}\\)<\/p>\n<p>This is Ostwald&#8217;s process to produce nitric oxide.<\/p>\n<p>(b) \\(\\mathrm{H}_{2} \\mathrm{SO}_{4}+2 \\mathrm{NaOH} \\rightarrow \\mathrm{Na}_{2} \\mathrm{SO}_{4}+2 \\mathrm{H}_{2} \\mathrm{O}\\)<\/p>\n<p>(Sulfuric (Sod. (Sod. (Water) acid) Hydroxide) Sulfate)<\/p>\n<p>(c) \\(\\mathrm{FeS}(s)+2 \\mathrm{HCl}(a q) \\rightarrow \\mathrm{FeCl}_{2}(s)+\\mathrm{H}_{2} \\mathrm{~S}(g)\\)<\/p><\/div>\n<\/div>\n<div class=\"xc-qblock\" id=\"icse-chemistry-2023-q8-iv\">\n<div class=\"xc-qhead\"><div class=\"xc-qnum\">iv<\/div><div class=\"xc-qtext\"><p>Choose the answer from the list which fits in the description:<\/p>\n<div class=\"mathjax-overflow\">\\[\n\\left[\\mathrm{CCI}_{4}, \\mathrm{PbO}, \\mathrm{NaCl}, \\mathrm{CuO}, \\mathrm{NH}_{4} \\mathrm{Cl}\\right]\n\\]<\/div>\n<p>(a) A compound which undergoes thermal dissociation.<\/p>\n<p>(b) An amphoteric oxide.<\/p>\n<p>(c) A compound which is a non-electrolyte. <strong>[3]<\/strong><\/p><\/div><\/div>\n<div class=\"xc-ans-toggle\" role=\"button\" tabindex=\"0\" aria-expanded=\"false\"><span class=\"xc-toggle-icon\">\u25bc<\/span> View Answer &amp; Solution<\/div>\n<div class=\"xc-explanation\"><div class=\"xc-expl-head\">Answer &amp; Solution<\/div><p>(a) \\(\\mathrm{NH}_{4} \\mathrm{Cl}\\)<\/p>\n<p>(b) PbO : It behaves both as acidic and basic oxide.<\/p>\n<p>(c) \\(\\mathrm{CCl}_{4}\\) : It is formed due to covalent bonding.<\/p><\/div>\n<\/div>\n<\/div>\n<\/div>\n\n\n\n<p><\/p>\n\n\n\n<p><\/p>\n","protected":false},"excerpt":{"rendered":"<p><span class=\"rt-reading-time\" style=\"display: block;\"><span class=\"rt-label rt-prefix\">Reading Time: <\/span> <span class=\"rt-time\">24<\/span> <span class=\"rt-label rt-postfix\">minutes<\/span><\/span> ICSE Class 10 Chemistry PYQ Practice the complete ICSE Class 10 Chemistry 2023 Question Paper with Solutions, including MCQs, chemical [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_lmt_disableupdate":"","_lmt_disable":"","site-sidebar-layout":"default","site-content-layout":"","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"var(--ast-global-color-4)","background-image":"","background-repeat":"repeat","background-position":"center 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